Please refer to Class 10 Social Science Sample Paper Term 2 With Solutions Set E below. These Class 10 Science Sample Papers will help you to get more understanding of the type of questions expected in the upcoming exams. All sample guess papers for Social Science Class 10 have been designed as per the latest examination pattern issued by CBSE. Please practice all Term 2 CBSE Sample Papers for Social Science in Standard 10.
Sample Paper Term 2 Class 10 Social Science With Solutions Set E
Section – A
1. The atomic number of three elements are given below

Write the symbol of the element which belongs to
(i) Group 13,
(ii) Group 15,
of the periodic table.
Answer. (i) A –
(ii) B –
2. What are isomers? Draw the structures of two isomers of butane, C4H10
Answer. Isomers are compounds having the same molecular formula but different structures.
The two isomers of butane, C4HI0 are:

3. Illustrate the following with the help of suitable diagrams:
(i) Regeneration in Planaria.
(ii) Budding in Hydra.
Answer.

4. a) Name the parts labeled A, B, C, D .Answer.4. a) Name the parts labeled A, B, C, D .

Answer. • A—-Fallopian Tube
• B——Ovary
• C——-Uterus
• D—— Cervix
5. A husband has 46 chromosomes. His wife has 46 chromosomes. Then why do not their offspring has 46 pairs of chromosomes which is obtained by the fusion of male and female gametes? Support your answer with a neat illustration.
OR
In an asexually reproducing species, if a trait X exists in 7% of a population and trait Y exists in 80% of the same population, which of the two trait is likely to have arisen earlier? Give reason.
Answer. Gametes do not possess the same number of chromosomes as are present in individuals. Meiosis occurs prior to formation of gametes. This reduces the number of chromosomes to one half in gametes. In humans, the gametes carry only 23 chromosomes (one half of 46). Fusion of two gametes restores the number of 46 chromosomes in the zygote. Therefore, the human offspring does not have 46 pairs of chromosomes.

OR
Trait Y which exists in 80% (larger fraction) of the population, is likely to have arisen earlier because in asexual reproduction, identical copies of DNA are produced and variations don’t occur.
New traits come in the population due to sudden mutation and then are inherited .80 % of the population with trait Y is likely to have been replicating that trait for a longer period than7% of population with trait X.
6. What is Fleming’s left hand rule? What is the direction of the force acting on the proton

OR
Identify North and south poles of a magnet in the figure. What is the direction of magnetic field lines outside a bar magnet?

Answer. According to Fleming’s left hand rule, the force acting on a current carrying conductor placed at right angles to a magnetic field is perpendicular to the directions of current {i.e. flow of positive charges) and the magnetic field. The arrow showing the direction of proton represents the direction of current in a conductor, therefore, the force acting on the conductor is perpendicular to the plane of the paper and in upward direction.
OR

From North Pole to South pole outside the magnet.
7. In the following food chain, 5 J of energy is available to man. How much energy was available at the producer level?
Plants → Sheep → Man
OR
What is depicted in the scheme? Name any two non-biodegradable wastes.

Answer. Man 5 J, sheep 5 x 10 = 50 J, plants 50 x 10 = 500 J
OR
It is a food chain that is depicting 10% law of energy.
Waste plastic articles, polythene bags, many pesticides like DDT
Section – B
8. The elements of the third period of the Periodic Table are given below:
(a) Which atom is bigger, Na or Mg? Why?
(b) Identify the most (i) metallic and (ii) non-metallic element in Period3

Answer. (a) Na is bigger because size of atom decreases on moving left to right in a period.
(b) Most metallic- sodium, non-metallic- chlorine
9. a) Which of the following belong to the same homologous series?
C3H8, C4H8, C4H6, C3H6.
(b) A compound with molecular formula C2H6O is used as a fuel. Identify the compound
(c) Select the saturated hydrocarbons from the following: C3H6; C5H10; C4H10; C6H14; C2H4
OR
Draw three structural isomers of pentane?
Answer. a. C3H6 and C4H8 belong to the same homologous series which is alkenes with general formula CnH2n.
b. The compound is ethanol with formula C2H5OH.
c. The compounds C4H10 (butane) and C6H14 (hexane) are saturated hydrocarbons. They correspond to the molecular formula CnH2n+2.
OR

10. A blue colour flower plant denoted by BB is cross bred with that of white colour
flower plant denoted by bb.
(a) State the colour of flower you would expect in their F1 generation plants.
(b) What must be the percentage of white flower plants in F2 generation if flowers of F1 plants are self-pollinated?
(c) State the expected ratio of the genotypes BB and Bb in the F2 progeny
Answer.

11. (a) Though same current flows through the electric line wires and the filament of bulb, yet only the filament glows. Why?
(b) The temperature of the filament of bulb is 2700°C when it glows. Why does it not get burnt up at such high temperature?
(c) What is the commercial unit of electric energy? Convert it into joules.
Answer. (a) Electric line wires offer extremely low resistance to the flow of current, so they do not glow because negligible heat is produced in it.
The filament of bulb glows because it becomes red hot due to large amount of heat produced, as it offers high resistance to the flow of current through it.
(b) The filament of bulb when it glows at 2700°C does not get burnt because the tungsten metal of filament has
(i) a very high melting point (of 3380°C) and
(ii) a high resistivity
(c) Kilowatt hour – Commercial unit of electrical energy
1 kWh = 1000 Wh = 1000 J/S x 3600 sec
= 3600000 J = 3.6 x106J
12. (a) A current of 4 A flows through a 12V car headlight bulb for 10 minutes. How much energy transfer occurs during this time?
(b) A heating element is marked 210 V, 630 W. What is the current drawn by the element when connected to a 210 V D.C. mains? What is the resistance of the element?
OR
A household uses the following electric appliances:
(i) Refrigerator of rating 400 W for ten hours each day.
(ii) Two electric fans of rating 80 W each for twelve hours each day.
(iii) Six electric tubes of rating 18 W each for 6 hours each day.
Calculate the electricity bill of the household for the month of June if the cost per unit of electric energy is ₹ 3.00.
Answer. 12.(a) Given : I = 4 A, V = 12 V, t = 10 min = 600 s
Energy transferred = V. I. t = 12 × 4 × 600 = 28800 J.
(b) Given, P = 630 W, V = 210V
Current drawn, I = PV=630/210 = 3A
Resistance =voltage/current =210/3= 70 ohms
OR
Energy consumed by refrigerator of rating 400 W for ten hours each day
= P × t = 400 W × 10 Aw = 4001000 kW × 10 h = 4.0 kWh
Energy consumed by two electric fans of rating 80 W each for twelve hours each day
= 2 × P × t = 2 × 80W × 12h = 1601000 kW × 12 h = 1.92 kWh
Energy consumed by six electric tubes of rating 18 W each for 6 hours each day
= 6 × P × t = 6 × 18W × 6h = 1081000 W × 6 h = 0.648 kWh
Total energy consumed in the month of June (30 days)
= (4.0 + 1.92 + 0.648) × 30 kWh = 6.568 × 30 = 197.04 kWh
Electricity bill for the month of June
= 197.04 × 3 = 591.12 = Rs 591 (approx.)
13. (a) What is an ecosystem? List its two main components.
(b) We do not clean ponds or lakes but an aquarium needs to be cleaned regularly. Explain.
(c) Write the full form of CFC.
Answer. (a) Ecosystem: It is self contained ecological system, which consists of a distinct, biotic community and the physical environment both interacting and exchanging materials between them.
Main Components,
1. Biotic, e.g., producers, consumers
2. Abiotic, e.g., climatic factors, inorganic nutrients
(b) Cleaning an aquarium:
An aquarium is an artificial system which is also incomplete due to absence of producers, food chains and decomposers. There is no recycling and self cleaning. However, a pond or a lake is a self sustained, natural and complete ecosystem where there is perfect recycling of nutrients.
(c) Chlorofluorocarbon.
Section – C
This section has two case-based questions (14 and 15). Each case is followed by 03 sub-questions (a, b and c) Parts a and b are compulsory .However, an internal choice has been provided in part c.
14. A scientist cross pure-bred tall (dominant) pea plant with pure-bred dwarf (recessive) pea plant he will get pea plants of F1 generation. If now self-cross the pea plant of F2 generation is done, then we obtain pea plants of F2 generation.
(a) What do the plants of F2 generation look like?
(b) State the ratio of tall plants to dwarf plants in F2 generation.. Write the full form of DNA.
(c) State the type of plants not found in F2 generation but appeared in F2 generation, mentioning the reason for the same
OR
(c) How does the creation of variations in a species promote survival?
Answer. (a) All plants of F1 generation will be tall plants.
(b) 3:1, Deoxyribonucleic acid
(c) Dwarf trait is recessive trait which was not expressed in the F1 generation; the recessive trait gets expressed in the F2 generation after self pollination
OR
Variations promote the survival of the species as they allow them to adapt and survive to the changing environment and conditions. Different species have different kinds of advantages depending on the nature of variation.
15. A wire made up of copper is wound on a cylindrical core. The outer surface of the wire is insulated, therefore it carry current only inside it and not along its out surface. It also protects leakage of current from one turn to another. This arrangement will be referred to as a coil in this experiment. Now a student connects this coil to a galvanometer. What would happen if a bar magnet is
(i) Pushed into the coil with its north pole entering first?
(ii) Pulled out of the bar magnet? What is the principle of electric motor?
(iii) Held stationary inside the coil
OR
(iii) What is The shape of the magnetic field lines produced by a current carrying conductor?
Answer. (i) A deflection is observed in the galvanometer due to the induced current because of the changing magnetic flux (increasing) through the turns of the coil connected to the galvanometer.
(ii) A deflection is again observed in the galvanometer, as when it is pulled out, the flux linked with the coil due to the bar magnet decreases. Hence a current flows in the coil to reduce the change in flux. The deflection can be observed in the opposite direction as compared with the previous case. The principle of electric motor is when a rectangular coil is placed in a magnetic field and current is passed through it ,the coil rotates as a result of forces acting on the coil.
(iii) No deflection is observed in the galvanometer. The flux linked with the coil due to the magnetic field is at a constant. Hence no current is induced due to the bar magnet.
OR
Concentric circles