Please refer to the below Haloalkanes and Haloarenes important questions for Class 12 Chemistry. These questions and answers have been prepared as per the latest NCERT Book for Class 12 Chemistry. Students should go through chapter wise Class 12 Chemistry Important Questions designed as per the latest examination pattern issued by CBSE.
Very Short Answer Questions :
Question. Write the structure of the following compound :
1-bromo-4-sec-butyl-2-methylbenzene
Answer :

Question. Write the major products in the following :

Answer :

Question. Draw the structure of 2-bromopentane.
Answer :

Question. Write the IUPAC name of (CH3)2CHCH(Cl)CH3.
Answer : 2-Chloro-3-methyl butane
Question. Write the IUPAC name of the following compound :

Answer :

Question. Why does p-dichlorobenzene have a higher m.p. than its o- and m-isomers?
Answer : p-Dichlorobenzene has higher melting point than those of o-and m-isomers because it is more symmetrical and packing is better in solid form. Hence, it has stronger intermolecular force ofattraction than o-and m-isomers.

Question. How do you convert :
Propene to 1-iodopropane ?
Answer :

Question. Write the IUPAC name of

Answer : 4-Chloropent-1-ene
Question. Complete the following chemical equation :
CH3CH2CH = CH2 + HBr →Peroxide …
Answer :

Question. Explain the following :
Alkyl halides, though polar, are immiscible with water.
Answer : Alkyl halides are polar but are insoluble in water because energy required to break the intermolecular H – bond among water molecules is much higher than energy released by water halide interaction.
Question.


which is more reactive towards SN1 reaction and why?
Answer : The SNl reaction proceeds through carbocation formation thus, the compound which forms more stable carbocation will be more reactive.

As, 2° carbocation is more stable than 1° carbocation thus, 2-chlorobutane is more reactive towards SNl reaction.
Question. Account for the following :
Grignard’s reagents should be prepared under anhydrous conditions.
Answer : Grignard reagents react with water to form alkanes.

So, they must be prepared under anhydrous conditions.
Question. Which halogen compound in each of the following pairs will react faster in SN2 reaction :
(i) CH3Br or CH3I
(ii) (CH3)3CCl or CH3Cl
Answer : (i) CH3I will give faster SN2 reaction.
(ii) CH3Cl will give faster SN2 reaction.
Question. Why are alkyl halides insoluble in water?
Answer : Alkyl halides are polar but are insoluble in water because energy required to break the intermolecular H – bond among water molecules is much higher than energy released by water halide interaction.
Question. Write the structure of an isomer of compound C4H9Br which is most reactive towards SN1 reaction.
Answer :

Short Answer Questions :
Question. Complete the following reaction equations :

Answer : (i)

(ii)

Question. Which would undergo SN2 reaction faster in the following pair and why?
CH3 — CH2 — Br and CH3 — CH2 — I
Answer : Since I– is a better leaving group than Br–, thus, CH3CH2I undergoes SN2 reaction faster than CH3CH2Br.
Question. Answer the following :
Haloalkanes easily dissolve in organic solvents, why?
Answer : Haloalkanes dissolve in organic solvents because the intermolecular attractions between haloalkanes and organic solvent molecules have the same strength as in the separate haloalkanes and solvent molecules.
Question. Compute the following reaction equations:

Answer :(i)

(ii)

(iii)

Question. Give the IUPAC names of the following compounds :

Answer : (i) 2-Bromobutane
(ii) 1,3-Dibromobenzene
(iii) 3-Chloropropene
Question. Write the IUPAC name of the following compound :
(CH3)3CCH2Br
Answer :

Question. Write the IUPAC name of

Answer : 4-Bromo-4-methylpent-2-ene
Question. Give reason :
n-Butyl bromide has higher boiling point than t-butyl bromide.
Answer : n-Butyl bromide, being a straight chain molecule have strong intermolecular forces whereas t-butyl bromide being a branched chain molecule have weaker intermolecular forces due to smaller surface area.
Hence, boiling point of n-butyl bromide is higher than that of t-butyl bromide.
Question. Account for the following :
Grignard’s reagents should be prepared under anhydrous conditions.
Answer : Grignard reagents react with water to form alkanes.

So, they must be prepared under anhydrous conditions.
Question. Explain why
(i) the dipole moment of chlorobenzene is lower than that of cyclohexyl chloride?
(ii) alkyl halides, though polar, are immiscible with water?
Answer : (i) There are two reasons :
(a) In case of chlorobenzene, carbon to which chlorine is attached is sp2 hybridised and is more electronegative than the corresponding carbon in cyclohexyl chloride which is sp3 hybridised. So the net dipole moment is lower in chlorobenzene.
(b) In chlorobenzene C—Cl bond has some double bond character so its bond length is smaller.
Hence dipole moment is smaller than cyclohexyl chloride which has a longer C—Cl single bond.

(ii) Alkyl halides are polar but are insoluble in water because energy required to break the intermolecular H – bond among water molecules is much higher than energy released by water halide interaction.
Question. Draw the structure of major monohalo product in the following reaction :

Answer :

Question. Why is (±)-butan-2-ol is optically inactive?
Answer : The (±)-Butan-2-ol is optically inactive because it exist in two enantiomeric forms which are non-superimposable mirror images of each other. Both the isomers are present in equal amounts therefore, it does not rotate the plane of polarized light and is optically inactive.

Question. Draw the structure of major monohalogen product formed in the following reaction :

Answer :

Question. State the IUPAC name of the following compound :

Answer : 1-Bromobut-2-ene
Question. Write the mechanism of the following reaction :
CH3CH2OH →HBr CH3CH2Br + H2O
Answer :

Question. Write the IUPAC name of the following compound :

Answer : 2-Bromo-4-chloropentane
Question. Write the structure of the compound 1-chloro- 4-ethylcyclohexane.
Answer :

Question. Draw the structure of major monohalo product in each of the following reactions :

Answer :

Question. Write the structure of the compound :
4-tert-butyl-3-iodoheptane
Answer :

Question. How may methyl bromide be preferentially converted to methyl isocyanide?
Answer : KCN is predominantly ionic and provides cyanide ions in solution
CH3Br + KCN → CH3C ≡ N + KBr
Methyl bromide Methyl cyanide
AgCN is mainly covalent in nature and nitrogen is free to donate electron pair forming isocyanide as main product.
CH3Br + AgCN → CH3N ≡ C + AgBr
Methyl bromide Methyl isocyanide